0.5x^2+3x+2=55

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Solution for 0.5x^2+3x+2=55 equation:



0.5x^2+3x+2=55
We move all terms to the left:
0.5x^2+3x+2-(55)=0
We add all the numbers together, and all the variables
0.5x^2+3x-53=0
a = 0.5; b = 3; c = -53;
Δ = b2-4ac
Δ = 32-4·0.5·(-53)
Δ = 115
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{115}}{2*0.5}=\frac{-3-\sqrt{115}}{1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{115}}{2*0.5}=\frac{-3+\sqrt{115}}{1} $

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